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What force exert by parachutes

Drop any object from a plane and the downward force due to the mass will eventually be matched by an upward force due to air resistance (terminal velocity). This terminal velocity depends on the objects drag coefficient, what the parachute does is present a drag coefficient sufficient to give the required terminal velocity for landing .
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You need no more than say 6 metres / second landing velocity, effectively this is the terminal velocity with the chute open.
Using body mass of 80 kg and acceleration due to gravity of 10 (m/s)/s,
this gives a downward force of ( 80 * 10 ) 800 newtons.
To balance this at landing velocity, you need a drag coefficient calculated from:
800 = velocity2 * drag coefficient , so:
drag coefficient = 800 / velocity2 = 22.22
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Compare this to the pre chute deployment velocity of around 80 metres / second, giving a drag coefficient of:
drag coefficient = 800 / 6400 = 0.125

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